Borys wrote:Let me see... 3 characters picked from 12... 12*11*10 = 1320 combinations = 1320 custom openings. Yeah, I know it would be nice touch.
Wrong. Ill explain that using spanish words cos i dnt know english ones for this but u using permutaciones and they are Coeficiente binomial.
The diference is order doesent matter and also I guess u can use only 3 chars if u do a custom game. the 4th if u get a 4th one will b random.
So:
"N/K"=N!/K!(N-K)!
12=N
3=K
So... 12!/ 3!(12-3)!
12*11*10*9*8*7*6*5..../3*2*1(9*8*7....)
479001600/2177280=220 Diferent starting texts.